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The energy required to remove the elect...

The energy required to remove the electron from a singly ionized Helium atom is `2.2` times the energy required to remove an electron from Helium atom. The total energy required to ionize the Helium atom ompletelyis:

A

34 ev

B

20 eV

C

79 eV

D

109 eV

Text Solution

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The correct Answer is:
To solve the problem of finding the total energy required to completely ionize a helium atom, we can break it down into steps. ### Step 1: Understand the Energy Required for Ionization The energy required to remove an electron from a singly ionized helium atom (He⁺) is given as 2.2 times the energy required to remove an electron from a neutral helium atom (He). ### Step 2: Define the Energies Let: - \( E_n \) = Energy required to remove an electron from a singly ionized helium atom (He⁺). - \( E_0 \) = Energy required to remove an electron from a neutral helium atom (He). From the problem statement, we have: \[ E_n = 2.2 \times E_0 \] ### Step 3: Calculate the Energy for He⁺ The energy required to remove an electron from a singly ionized helium atom can be calculated using the formula for ionization energy: \[ E_n = -\frac{Z^2 \cdot 13.6 \, \text{eV}}{n^2} \] where \( Z \) is the atomic number and \( n \) is the principal quantum number. For helium, \( Z = 2 \) and for the ground state \( n = 1 \): \[ E_n = -\frac{2^2 \cdot 13.6 \, \text{eV}}{1^2} = -54.4 \, \text{eV} \] ### Step 4: Calculate the Energy for Neutral Helium Now, substituting \( E_n \) into the equation \( E_n = 2.2 \times E_0 \): \[ -54.4 \, \text{eV} = 2.2 \times E_0 \] To find \( E_0 \): \[ E_0 = \frac{-54.4 \, \text{eV}}{2.2} \] Calculating this gives: \[ E_0 = -24.727 \, \text{eV} \approx -24.7 \, \text{eV} \] ### Step 5: Calculate the Total Energy Required for Complete Ionization The total energy required to completely ionize the helium atom is the sum of the energies required to remove both electrons: \[ E_{\text{total}} = E_n + E_0 \] Substituting the values we calculated: \[ E_{\text{total}} = -54.4 \, \text{eV} + (-24.7 \, \text{eV}) \] \[ E_{\text{total}} = -79.1 \, \text{eV} \] Since we are interested in the magnitude of energy required, we take the positive value: \[ E_{\text{total}} \approx 79 \, \text{eV} \] ### Final Answer The total energy required to completely ionize the helium atom is approximately **79 eV**.
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Knowledge Check

  • the energy required to excite an electron in hydrogen atom to its first excited state is

    A
    `8.5eV`
    B
    `10.2eV`
    C
    `12.7eV`
    D
    `13.6eV`
  • The binding energy of the electron in the ground state of He atom is equal to E_(0)=24.6 eV . Find the energy required to remove both the electrons from the atom.

    A
    49.2eV
    B
    54.4eV
    C
    79eV
    D
    108.8eV
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