Home
Class 12
MATHS
The arithmetic mean of two positive numb...

The arithmetic mean of two positive numbers a and b exceeds their geometric mean by 2 and the harmonic mean is one - fifth of the greater of a and b, such that `alpha=a+b and beta=|a-b|`, then the value of `alpha+beta^(2)` is equal to

A

96

B

234

C

74

D

84

Text Solution

Verified by Experts

The correct Answer is:
C
Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

If arithmetic mean of two positive numbers is A, their geometric mean is G and harmonic mean H, then H is equal to

The arithmetic mean of two positive numbers a and b exceeds their geometric mean by (3)/(2) and the geometric mean exceeds their harmonic mean by (6)/(5) . If a+b=alpha and |a-b|=beta, then the value of (10beta)/(alpha) is equal to

If the arithmetic means of two positive number a and b (a gt b ) is twice their geometric mean, then find the ratio a: b

The arithmetic mean between two numbers is A and the geometric mean is G. Then these numbers are:

The arithmetic mean of two numbers is 6 and their geometric mean G and harmonic mean H satisfy the relation G^2+3H=48 .Find the two numbers.

The arithmetic mean of two positive numbers is 6 and their geometric mean G and harmonic mean H satisfy the relation G^(2)+3H=48 . Then the product of the two numbers is

If the arithmetic mean of two numbers a and b, a>b>0 , is five times their geometric mean, then (a+b)/(a-b) is equal to:

The arithmetic mean between two distinct positive numbers is twice the geometric mean between them. Find the ratio of greater to smaller. ​

The geometric mean G of two positive numbers is 6 . Their arithmetic mean A and harmonic mean H satisfy the equation 90A+5H=918 , then A may be equal to:

The harmonic mean of two positive numbers a and b is 4, their arithmetic mean is A and the geometric mean is G. If 2A+G^(2)=27, a+b=alpha and |a-b|=beta , then the value of (alpha)/(beta) is equal to

Home
Profile