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The change in bond angle as the s - char...

The change in bond angle as the s - character of hybridized orbital decreases is ,

A

Decreases

B

Increases

C

Does not change

D

Become zero

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The correct Answer is:
To solve the question regarding the change in bond angle as the s-character of hybridized orbitals decreases, we will follow these steps: ### Step 1: Understand Hybridization Hybridization involves the mixing of atomic orbitals to form new hybrid orbitals that can accommodate the bonding electrons. The s-character refers to the proportion of s orbital character in these hybrid orbitals. **Hint:** Remember that hybridization can involve different combinations of s and p orbitals, leading to different geometries and bond angles. ### Step 2: Identify the Relationship Between s-character and Bond Angle The bond angle is influenced by the s-character of the hybrid orbitals. As the s-character increases, the bond angle tends to increase. This is because s orbitals are spherical and allow for greater electron density around the nucleus, which leads to increased repulsion between bonding pairs of electrons. **Hint:** Think about how the shape of the orbitals affects the spatial arrangement of electrons. ### Step 3: Analyze Different Types of Hybridization - **sp³ Hybridization:** 25% s-character, bond angle ~109.5° (tetrahedral geometry). - **sp² Hybridization:** 33.3% s-character, bond angle ~120° (trigonal planar geometry). - **sp Hybridization:** 50% s-character, bond angle ~180° (linear geometry). As we see, as the s-character decreases from sp to sp² to sp³, the bond angles also decrease. **Hint:** Create a table to visualize the relationship between hybridization type, s-character, and bond angle. ### Step 4: Conclude the Relationship Since the bond angle is directly proportional to the s-character, if the s-character decreases, the bond angle must also decrease. This means that as we move from sp to sp³ hybridization, the bond angle decreases. **Hint:** Consider how the electron repulsion and spatial arrangement change with varying s-character. ### Final Conclusion Thus, the change in bond angle as the s-character of hybridized orbitals decreases is that the bond angle decreases. **Answer:** The bond angle decreases as the s-character of hybridized orbitals decreases.
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Knowledge Check

  • Assertion: Hybridisation influences the bond length and bond enthalpy in organic compound. Reason: More the s character of hybrid orbital, shorter and stornger will be the bond.

    A
    If both assertion and reason are true and reason is the correct explanation of assertion
    B
    If both assertion and reason are true but reason is not the correct explanation of assertion
    C
    If assertion is true but reason is false.
    D
    If both assertion and reason are false.

  • Bond X is made by the overlap of which type of hybridized orbitals ?

    A
    `sp and sp^3`
    B
    `sp and sp^2`
    C
    `sp^2 and sp^3`
    D
    none of these

    • Similar Questions

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    Most of the polyatomic molecules except a few such as CO_(2) and CS_(2) are linear or angular with a bond angle generally somewhat greater than 90^(@) A bond angle is defined as the angle between the direction of two covalent bonds Since the atoms in molecules are in constant motion with respect to each other they are not expected to have a fixed value of bond angle Repulsion between non-bonded atoms alone does not provide an adequate explanation Hybridisation of bonding orbitals an adequate explanation Hybridisation of bonding orbitals also plays a very important role in detrmining the value of bond angle It has been observed that in hybridisation as the s-character of hybrid orbital increases the bond angle increases In P_(4) molecule phosphorous atoms are tetrahedrally arranged The angle P-P-P in the molecule is .

    Which is correct statement ? As the s-character of a hybrid orbital decreases (I) The bond angle decreases (II) The bond strength increases (III) The bond length increases (IV) Size of orbitals increases

    Which of the following statement is correct : As the %s-character of a hybrid orbital decreases

    An sp^(3) hybrid orbital possesses

    The decreasing order of the basic character is :

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