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The set of four quantum number not possi...

The set of four quantum number not possible from the following .

A

`n = 3 , l =0, m = 0 , s = -1/2`

B

`n = 3 , l =2, m = 0 , s = -1/2`

C

`n = 3 , l =3, m = -3 , s = -1/2`

D

`n = 3 , l =2, m = -2 , s = -1/2`

Text Solution

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The correct Answer is:
To determine which set of quantum numbers is not possible, we need to analyze the four quantum numbers: principal quantum number (n), azimuthal quantum number (l), magnetic quantum number (m_l), and spin quantum number (m_s). ### Step-by-Step Solution: 1. **Understanding Quantum Numbers**: - **Principal Quantum Number (n)**: This number indicates the main energy level of an electron in an atom. It can take positive integer values (n = 1, 2, 3, ...). - **Azimuthal Quantum Number (l)**: This number describes the subshell and can take values from 0 to (n-1). For example, if n = 3, then l can be 0, 1, or 2. - **Magnetic Quantum Number (m_l)**: This number indicates the orientation of the orbital and can take values from -l to +l, including zero. - **Spin Quantum Number (m_s)**: This number describes the spin of the electron and can be either +1/2 or -1/2. 2. **Analyzing the Options**: - **Option 1**: n = 3, l = 0, m_l = 0, m_s = -1/2 - Here, n = 3 is valid, l = 0 is valid (s orbital), m_l = 0 is valid, and m_s = -1/2 is valid. This set is possible. - **Option 2**: n = 3, l = 2, m_l = 0, m_s = +1/2 - Here, n = 3 is valid, l = 2 is valid (d orbital), m_l = 0 is valid, and m_s = +1/2 is valid. This set is possible. - **Option 3**: n = 3, l = 3, m_l = 0, m_s = -1/2 - Here, n = 3 is valid, but l = 3 is not valid because l must be less than n (l can be 0, 1, or 2 when n = 3). Therefore, this set is **not possible**. - **Option 4**: n = 4, l = 2, m_l = -2, m_s = +1/2 - Here, n = 4 is valid, l = 2 is valid (d orbital), m_l = -2 is valid (since m_l can range from -l to +l), and m_s = +1/2 is valid. This set is possible. 3. **Conclusion**: - The only set of quantum numbers that is not possible is **Option 3: n = 3, l = 3, m_l = 0, m_s = -1/2**. ### Final Answer: **Option 3** is the set of quantum numbers that is not possible.
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Knowledge Check

  • Which set of quantum numbers is possible for the last electron of Mg^(+) ion

    A
    n=3,l=2,m=0,s=+1/2
    B
    n=2,l=3,m=0,s=+1/2
    C
    n=1,l=0,m=0,s=+1/2
    D
    n=3,l=0,m=0,s=+1/2
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