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The weight of a body on the surface of t...

The weight of a body on the surface of the earth is 12.6 N. When it is raised to height half the radius of earth its weight will be

A

2.8 N

B

5.6 N

C

12.5 N

D

25.2 N

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Understand the weight of the body on the surface of the Earth. The weight of the body on the surface of the Earth is given as \( W = 12.6 \, \text{N} \). ### Step 2: Use the formula for gravitational force. The weight of the body can be expressed using the formula for gravitational force: \[ W = \frac{G M m}{R^2} \] where: - \( G \) is the gravitational constant, - \( M \) is the mass of the Earth, - \( m \) is the mass of the body, - \( R \) is the radius of the Earth. ### Step 3: Determine the new height. The body is raised to a height \( h = \frac{R}{2} \) (half the radius of the Earth). ### Step 4: Apply the formula for weight at height \( h \). When the body is at height \( h \), the weight can be calculated using the modified formula: \[ W' = \frac{G M m}{(R + h)^2} \] Substituting \( h = \frac{R}{2} \): \[ W' = \frac{G M m}{\left(R + \frac{R}{2}\right)^2} = \frac{G M m}{\left(\frac{3R}{2}\right)^2} = \frac{G M m}{\frac{9R^2}{4}} = \frac{4 G M m}{9 R^2} \] ### Step 5: Relate the new weight to the original weight. Since we know the original weight \( W = \frac{G M m}{R^2} \), we can express the new weight \( W' \) in terms of the original weight: \[ W' = \frac{4}{9} W \] ### Step 6: Substitute the known weight. Now, substituting the known weight: \[ W' = \frac{4}{9} \times 12.6 \, \text{N} \] ### Step 7: Calculate the new weight. Calculating this gives: \[ W' = \frac{4 \times 12.6}{9} = \frac{50.4}{9} \approx 5.6 \, \text{N} \] ### Conclusion The weight of the body when raised to a height of half the radius of the Earth is approximately \( 5.6 \, \text{N} \). ---
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