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The moment of inertia of a solid cylinde...

The moment of inertia of a solid cylinder about its axis is given by `(1//2)MR^(2)`. If this cylinder rolls without slipping the ratio of its rotational kinetic energy to its translational kinetic energy is -

A

`1:1`

B

`2:2`

C

`1:2`

D

`2:3`

Text Solution

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The correct Answer is:
To solve the problem of finding the ratio of the rotational kinetic energy to the translational kinetic energy for a solid cylinder rolling without slipping, we can follow these steps: ### Step 1: Understand the formulas for kinetic energy The rotational kinetic energy (Re) and translational kinetic energy (Te) are given by the following formulas: - Rotational Kinetic Energy: \[ Re = \frac{1}{2} I \omega^2 \] - Translational Kinetic Energy: \[ Te = \frac{1}{2} mv^2 \] ### Step 2: Substitute the moment of inertia The moment of inertia (I) for a solid cylinder about its axis is given by: \[ I = \frac{1}{2} m R^2 \] where \(m\) is the mass of the cylinder and \(R\) is its radius. ### Step 3: Relate angular velocity and linear velocity For a cylinder rolling without slipping, the relationship between angular velocity (\(\omega\)) and linear velocity (\(v\)) is: \[ \omega = \frac{v}{R} \] ### Step 4: Substitute I and \(\omega\) into the kinetic energy formulas Now, substituting \(I\) and \(\omega\) into the equation for rotational kinetic energy: \[ Re = \frac{1}{2} \left(\frac{1}{2} m R^2\right) \left(\frac{v}{R}\right)^2 \] This simplifies to: \[ Re = \frac{1}{2} \cdot \frac{1}{2} m R^2 \cdot \frac{v^2}{R^2} = \frac{1}{4} mv^2 \] ### Step 5: Write the ratio of Re to Te Now, we can write the ratio of the rotational kinetic energy to the translational kinetic energy: \[ \frac{Re}{Te} = \frac{\frac{1}{4} mv^2}{\frac{1}{2} mv^2} \] ### Step 6: Simplify the ratio The \(mv^2\) terms cancel out: \[ \frac{Re}{Te} = \frac{\frac{1}{4}}{\frac{1}{2}} = \frac{1}{4} \cdot \frac{2}{1} = \frac{1}{2} \] ### Step 7: Conclusion Thus, the ratio of the rotational kinetic energy to the translational kinetic energy is: \[ \frac{Re}{Te} = \frac{1}{2} \] This can be expressed as a ratio of 1:2.
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