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A narrow parallel beam of light is incid...

A narrow parallel beam of light is incident on a transparent sphere of refractive index `n` if the beam finally gets focused at a point situated at a distance=`2xx("radius of sphere")` form the center of the sphere then find `n`?

A

`(4)/(3)`

B

`(3)/(2)`

C

`-(4)/(6)`

D

`(-2)/(3)`

Text Solution

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The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Understand the problem We have a transparent sphere with a refractive index \( n \) and a parallel beam of light incident on it. The light beam focuses at a distance of \( 2R \) from the center of the sphere, where \( R \) is the radius of the sphere. ### Step 2: Use the lens maker's formula The lens maker's formula for a spherical surface is given by: \[ \frac{n_2}{v} - \frac{n_1}{u} = \frac{n_2 - n_1}{R} \] Here, \( n_1 = 1 \) (the refractive index of air), \( n_2 = n \) (the refractive index of the sphere), \( v \) is the image distance, \( u \) is the object distance, and \( R \) is the radius of curvature. ### Step 3: Assign values to variables - The image distance \( v \) is given as \( 2R \). - The object distance \( u \) is initially considered to be at infinity since the beam is parallel. ### Step 4: Substitute values into the lens maker's formula Substituting \( n_1 \), \( n_2 \), and \( v \) into the lens maker's formula: \[ \frac{n}{2R} - \frac{1}{\infty} = \frac{n - 1}{R} \] Since \( \frac{1}{\infty} = 0 \), the equation simplifies to: \[ \frac{n}{2R} = \frac{n - 1}{R} \] ### Step 5: Cross-multiply to solve for \( n \) Cross-multiplying gives: \[ n = 2(n - 1) \] Expanding this: \[ n = 2n - 2 \] ### Step 6: Rearranging the equation Rearranging gives: \[ 2 = 2n - n \] \[ 2 = n \] ### Step 7: Conclusion Thus, the refractive index \( n \) is: \[ n = \frac{4}{3} \]
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