Which one of the following compounds show optical activity

Options

A.
B.
C.
D.

Answer

To determine which compound shows optical activity, we will analyze each compound based on the presence or absence of a plane of symmetry (POS). A compound is optically active if it does not have a plane of symmetry, meaning it cannot be superimposed on its mirror image.

### Step-by-Step Solution:

1. **Identify the Compounds**: We have four compounds labeled A, B, C, and D. We need to analyze each one for optical activity.

2. **Analyze Compound A**:
- Draw a plane of symmetry through the compound.
- Check if the compound can be divided into two identical halves.
- **Conclusion**: Since a plane of symmetry is present, Compound A is optically inactive.

3. **Analyze Compound B**:
- Draw a plane of symmetry through the compound.
- Check if the compound can be divided into two identical halves.
- **Conclusion**: There is no plane of symmetry present, meaning Compound B is optically active.

4. **Analyze Compound C**:
- Draw a plane of symmetry through the compound.
- Check if the compound can be divided into two identical halves.
- **Conclusion**: A plane of symmetry is present, so Compound C is optically inactive.

5. **Analyze Compound D**:
- Draw a plane of symmetry through the compound.
- Check if the compound can be divided into two identical halves.
- **Conclusion**: A plane of symmetry is present, indicating that Compound D is optically inactive.

6. **Final Conclusion**: Among the four compounds, only Compound B is optically active as it does not have a plane of symmetry.

### Answer:
The compound that shows optical activity is **Compound B**.