The number of isomers of the aromatic compound `C_8H_(10)` is :

Options

A. 3
B. 4
C. 2
D. 5

Answer

To determine the number of isomers for the aromatic compound \( C_8H_{10} \), we can follow these steps:

### Step 1: Identify the Structure
The molecular formula \( C_8H_{10} \) indicates that the compound is aromatic and contains a benzene ring. The presence of 10 hydrogen atoms suggests that there are substituents on the benzene ring.

### Step 2: Determine Possible Substituents
The possible substituents for \( C_8H_{10} \) can be derived from the fact that we can have different alkyl groups attached to the benzene ring. The most common substituents for this formula are:
- Ethyl group (\( C_2H_5 \))
- Methyl groups (\( C_1H_3 \))

### Step 3: Identify Isomers
Now, we can identify the isomers based on the different arrangements of these substituents:
1. **Ethylbenzene**: One ethyl group attached to the benzene ring.
2. **Ortho-xylene**: Two methyl groups attached to adjacent carbon atoms on the benzene ring.
3. **Meta-xylene**: Two methyl groups attached to carbon atoms separated by one carbon on the benzene ring.
4. **Para-xylene**: Two methyl groups attached to carbon atoms opposite each other on the benzene ring.

### Step 4: Count the Isomers
After identifying the structures, we can count the total number of distinct isomers:
- Ethylbenzene
- Ortho-xylene
- Meta-xylene
- Para-xylene

Thus, the total number of isomers for \( C_8H_{10} \) is **4**.

### Final Answer
The number of isomers of the aromatic compound \( C_8H_{10} \) is **4**.

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