Home
Class 12
CHEMISTRY
Which of the following is correct order ...

Which of the following is correct order of `sigma` - bond strength ?
I. 2s-2s
II. 2s-2p
III. 2p-2p
IV. 3s-3s

A

`I gt II gt III gt IV`

B

`III gt II gt I gt IV`

C

`IV gt I gt II gt III`

D

`III gt I gt II gt IV`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the correct order of sigma bond strength among the given options, we need to analyze the types of overlaps involved in each bond and how they relate to bond strength. ### Step-by-Step Solution: 1. **Understanding Sigma Bonds**: Sigma (σ) bonds are formed by the head-on overlap of atomic orbitals. The strength of a sigma bond is influenced by the type of overlap: - **pp overlap** (2p-2p) is stronger than - **sp overlap** (2s-2p) which is stronger than - **ss overlap** (2s-2s). 2. **Principal Quantum Number**: The bond strength is inversely proportional to the principal quantum number (n). A lower principal quantum number indicates a stronger bond. Therefore, bonds involving orbitals with lower principal quantum numbers will generally be stronger. 3. **Analyzing the Options**: - **I. 2s-2s**: This is an ss overlap. - **II. 2s-2p**: This is an sp overlap. - **III. 2p-2p**: This is a pp overlap. - **IV. 3s-3s**: This is an ss overlap, but with a higher principal quantum number (n=3). 4. **Comparing the Overlaps**: - The bond strength order based on overlap type is: - 2p-2p (III) > 2s-2p (II) > 2s-2s (I). - The bond strength for 3s-3s (IV) will be the weakest due to the higher principal quantum number. 5. **Final Order of Bond Strength**: Based on the above analysis, the correct order of sigma bond strength is: - III (2p-2p) > II (2s-2p) > I (2s-2s) > IV (3s-3s). Thus, the correct order of sigma bond strength is **3 > 2 > 1 > 4**.
Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

Which of the following is(are) correct for H atom ? 1s lt 2s lt 2p lt 3s lt 3p 1s lt 2s = 2p lt 3s = 3p 1s lt 2p lt 3d lt 4s 1s lt 2s lt 4s lt 3d The correct choice is

Arrange the following in order of increasing energy for hydrogen atom 1s 2s 2p 3s 3p 3d 4s 4p

Knowledge Check

  • Electronic configuratios of four elements A, B, C and D are given below: (i) 1s^(2)2s^(2)2p^(6) (ii) 1s^(2)2s^(2)2p^(4) (iii) 1s^(2)2s^(2)2p^(6)3s^(1) (iv) 1s^(2)2s^(2)2p^(5) Which of the following is the correct order of increasing tendency of gain electron:

    A
    AltCltBltD
    B
    AltBltCltD
    C
    DltBltCltA
    D
    DltAltBltC
  • Similar Questions

    Explore conceptually related problems

    Considering X axis as the inter nuclear axis, which out of the following will form a sigma bond (a) 1s and ls (b) ls and 2p_(x) (c ) 2p_(y) and 2p_(y) (d) 2p_(x) and 2p_(y) (e) 1s and 2s .

    Considering X-axis as the internucler axis, which out of the following atomic orbitals will from a sigma bond ? (a)1sand 1s" " (b) 1s and 2p_(x)" "(c )2p_(y)and2p_(y)" "(d)1s and2s.

    Electronic configuration of four elements A, B ,C and D are given below A) 1s^(2), 2s^(2), 2p^(6) B) 1s^(2), 2s^(2), 2p^(4) C) 1s^(2), 2s^(2), 2p^(6), 3s^(1) D) 1s^(2), 2s^(2), 2p^(5) Which of the following is the correct order of increasing tendency to gain electron?

    Which of the following electronic configurations has the lowest value of ionisation energy? Explain. a. 1s^(2) 2s^(2)2p^(6)3s^(1) b. 1s^(2) 2s^(2)2p^(6)

    Arrange the following orbital in the increasing order of the energy 3s, 4d, 2p, 4s,3p

    Arrange the following orbital in the increasing order of the energy 3s, 4d, 2p, 4s,3p

    Which of the following has the hihest electron gain enthalpy. Give reasons. (a) [Ne]3s^(2)3p^(3) (b) [Ne]3s^(2)3p^(4) ( c) [Ne]3s^(2)3p^(5) , (d) [Ne]3s^(2)3p^(6)