To solve the question regarding the reaction of iodine (I2) with aqueous solutions of NaF, NaBr, and NaCl, we will analyze the reactivity of iodine with each halide.
### Step-by-Step Solution:
1. **Understanding Reactivity of Iodine**:
- Iodine (I2) is a diatomic molecule and is known to be a relatively less reactive halogen compared to fluorine (F2), chlorine (Cl2), and bromine (Br2).
- The reactivity of halogens decreases down the group in the periodic table, meaning iodine is less reactive than fluorine, chlorine, and bromine.
2. **Reactions with NaF**:
- Sodium fluoride (NaF) contains fluoride ions (F-), which are very strong oxidizing agents.
- When I2 is introduced into an aqueous solution of NaF, there is no reaction because I2 cannot oxidize F- to F2 due to its lower reactivity.
3. **Reactions with NaBr**:
- Sodium bromide (NaBr) contains bromide ions (Br-).
- Similar to the case with NaF, when I2 is added to NaBr, no reaction occurs. I2 cannot oxidize Br- to Br2 because Br- is a stronger reducing agent than I2.
4. **Reactions with NaCl**:
- Sodium chloride (NaCl) contains chloride ions (Cl-).
- Again, when I2 is mixed with NaCl, no reaction takes place. I2 is unable to oxidize Cl- to Cl2 for the same reasons as above.
5. **Conclusion**:
- Since iodine does not react with any of the halide ions present in NaF, NaBr, or NaCl, we conclude that there is no reaction in any of these cases.
### Final Answer:
- Therefore, the correct answer is that no reaction occurs when iodine is passed through aqueous solutions of NaF, NaBr, and NaCl.
