When iodine is passed through aqueous solutions of NaF, NaBr and NaCl

Options

A. It gives mixture of `F_2 , Cl_2 and Br_2`
B. It gives chlorine
C. It gives bromine
D. None of these

Answer

To solve the question regarding the reaction of iodine (I2) with aqueous solutions of NaF, NaBr, and NaCl, we will analyze the reactivity of iodine with each halide.

### Step-by-Step Solution:

1. **Understanding Reactivity of Iodine**:
- Iodine (I2) is a diatomic molecule and is known to be a relatively less reactive halogen compared to fluorine (F2), chlorine (Cl2), and bromine (Br2).
- The reactivity of halogens decreases down the group in the periodic table, meaning iodine is less reactive than fluorine, chlorine, and bromine.

2. **Reactions with NaF**:
- Sodium fluoride (NaF) contains fluoride ions (F-), which are very strong oxidizing agents.
- When I2 is introduced into an aqueous solution of NaF, there is no reaction because I2 cannot oxidize F- to F2 due to its lower reactivity.

3. **Reactions with NaBr**:
- Sodium bromide (NaBr) contains bromide ions (Br-).
- Similar to the case with NaF, when I2 is added to NaBr, no reaction occurs. I2 cannot oxidize Br- to Br2 because Br- is a stronger reducing agent than I2.

4. **Reactions with NaCl**:
- Sodium chloride (NaCl) contains chloride ions (Cl-).
- Again, when I2 is mixed with NaCl, no reaction takes place. I2 is unable to oxidize Cl- to Cl2 for the same reasons as above.

5. **Conclusion**:
- Since iodine does not react with any of the halide ions present in NaF, NaBr, or NaCl, we conclude that there is no reaction in any of these cases.

### Final Answer:
- Therefore, the correct answer is that no reaction occurs when iodine is passed through aqueous solutions of NaF, NaBr, and NaCl.