When phosphate radical with ammonium molybdate, the colour of precipitate obtained as

Options

A. Green
B. Pink
C. Canary yellow
D. Violet

Answer

To determine the color of the precipitate formed when the phosphate radical reacts with ammonium molybdate, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
We have the phosphate radical (H₃PO₄) and ammonium molybdate (NH₄)₂MoO₄.

2. **Write the Reaction**:
The reaction between phosphate and ammonium molybdate can be represented as:
\[ H₃PO₄ + (NH₄)₂MoO₄ \rightarrow (NH₄)₃PO₄ \cdot 12MoO₃ + H₂O \]

3. **Identify the Precipitate**:
The product formed is ammonium phosphomolybdate, which is a complex compound.

4. **Determine the Color of the Precipitate**:
The precipitate formed, ammonium phosphomolybdate, is known to have a canary yellow color.

5. **Final Answer**:
Therefore, the color of the precipitate obtained when phosphate radical reacts with ammonium molybdate is canary yellow.

### Conclusion:
The correct option is **C: Canary Yellow**.

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