Paramagnetism is related to number of unpaired electrons.
Among `O_2` and `O_2^(-)` which is more paramagnetic?

Paramagnetism is related to number of unpaired electrons. Compare the stabilities of O_2 and O_2^(-) using bond order.

Indicate the number of unpaired electrons in (a) 'P'

The number of unpaired electrons in ""_(27)Co is

Which of the following has maximum number of unpaired electrons?

Presence of unpaired electrons makes a species paramagnetic. Each unpaired electron has a magnetic moment associated with its spin angular momentum and orbital angular momentum. For the compounds of the first series of transition metals, the contribution of the orbital angular momentum is effectively quenched and hence is considerably important. For these, the magnetic moment is determined by the number of unpaired electrons and is calculated by using the spin-only formula, i.e., mu = sqrt(n(n+2)) where n=number of unpaired electrons and mu =magnetic momentin (in Bohr magneton, B.M.). If n=1, then mu = 1.73 B.M . Which one of the following transition metal ions is paramagnetic?

The number of bonding and antibonding electrons in O_2^(2-) ion, respectively are

Give the number of electrons in thé species 'H_2^+, H_2' and 'O_2^+'.

The compound which does not show paramagnetism is