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What will be the acceleration due to gra...

What will be the acceleration due to gravity at height `h lt lt R` . Where R is radius of earth and g is acceleration to gravity on the surface earth

A

`(g)/((1 + (h)/(R))^(2))`

B

`g (1 - (2h)/(R))`

C

`(g)/((1 - (h)/(R))^(2))`

D

` g (1 - (h)/(R))`

Text Solution

AI Generated Solution

The correct Answer is:
To find the acceleration due to gravity at a height \( h \) where \( h \ll R \) (with \( R \) being the radius of the Earth and \( g \) being the acceleration due to gravity at the surface), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the formula for acceleration due to gravity at height \( h \)**: The general formula for the acceleration due to gravity at a height \( h \) above the Earth's surface is given by: \[ g' = \frac{g}{(1 + \frac{h}{R})^2} \] where \( g' \) is the acceleration due to gravity at height \( h \), \( g \) is the acceleration due to gravity at the surface, and \( R \) is the radius of the Earth. 2. **Assume \( h \) is very small compared to \( R \)**: Since \( h \ll R \), we can use the binomial approximation. The binomial expansion states that for small \( x \): \[ (1 + x)^n \approx 1 + nx \] Applying this to our formula, we can rewrite: \[ (1 + \frac{h}{R})^{-2} \approx 1 - 2\frac{h}{R} \] 3. **Substitute the approximation back into the formula**: Now substituting this approximation back into the formula for \( g' \): \[ g' = g \cdot (1 - 2\frac{h}{R}) \] 4. **Final expression for acceleration due to gravity at height \( h \)**: Thus, the acceleration due to gravity at height \( h \) is: \[ g' \approx g \left(1 - \frac{2h}{R}\right) \] ### Conclusion: The final expression for the acceleration due to gravity at a height \( h \) where \( h \ll R \) is: \[ g' \approx g \left(1 - \frac{2h}{R}\right) \]

To find the acceleration due to gravity at a height \( h \) where \( h \ll R \) (with \( R \) being the radius of the Earth and \( g \) being the acceleration due to gravity at the surface), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the formula for acceleration due to gravity at height \( h \)**: The general formula for the acceleration due to gravity at a height \( h \) above the Earth's surface is given by: \[ g' = \frac{g}{(1 + \frac{h}{R})^2} ...
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What is the value of the acceleration due to gravity at a height equal to radius of earth?

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Knowledge Check

  • What will be the acceleration due to gravity at height h if h gt gt R . Where R is radius of earth and g is acceleration due to gravity on the surface of earth

    A
    `(g)/((1+h/R)^(2))`
    B
    `g(1-(2h)/R)`
    C
    `(g)/((1-h/R)^(2))`
    D
    `g(1-h/R)`
  • Calculate the acceleration due to gravity at a height of 1600 km from the surface of the Earth. (Given acceleration due to gravity on the surface of the Earth g_(0) = 9.8 ms^(-2) and radius of earth, R = 6400 km).

    A
    `6.27 m//s^2`
    B
    `3.28 m//s^2`
    C
    `5.36 m//s^2`
    D
    `4.86 m//s^2`
  • The ratio of acceleration due to gravity at a height 3R above earth 's surface to the acceleration due to gravity on the surface of the earth is (where R=radius of earth)

    A
    `1/9`
    B
    `1/4`
    C
    `1/16`
    D
    `1/3`
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