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Complete the equation for the following ...

Complete the equation for the following fission process :
`""_(92)U^(235)+""_(0)n^(1)to""_(38)Sr^(0)+`…..

A

`""_(54)Xe^(143)+3""_(0)n^(1)`

B

`""_(54)Xe^(145)`

C

`""_(52)Xe^(142)`

D

`""_(54)Xe^(142)+""_(0)n^(1)`

Text Solution

Verified by Experts

In a nuclear reaction, atomic mass and charge remain conserved.
For a nuclear reaction to be completed the mass and charge number on both sides should be same.
If we complete the equation by choice a, then the reaction is
Total atomic number on LHS=`92+0=92`
`""_(92)U^(235)+""_(0)n^(1)to""_(38)Sr^(90)+""_(54)X^(143)+3""_(0)n^(1)`
Total atomic number on RHS
`38+54+0=92`
Total atomic number on LHS=`235+1=236`
Total atomic number on RHS
`=90+143+3xx1=236`
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Complete the equations for the following nuclear processes: (a) ._(17)^(35) Cl + ._(1)^(0)n rarr... + ._(2)^(4)He (b) ._(92)^(235)U + ._(0)^(1) n rarr ...+ ._(54)^(137)Xe + 2 _(0)^(1)n (c) ._(13)^(27) Al + ._(2)^(4) He rarr ... + ._(0)^(1) n (d) ...(n,p) ._(16)^(35) S (e) ._(94)^(239) Pu (alpha, beta^(-))...

The ._(92)U^(235) absorbs a slow neturon (thermal neutron) & undergoes a fission represented by ._(92)U^(235)+._(0)n^(1)rarr._(92)U^(236)rarr._(56)Ba^(141)+_(36)Kr^(92)+3_(0)n^(1)+E . Calculate: The energy released when 1 g of ._(92)U^(235) undergoes complete fission in N if m=[N] then find (m-2)/(5) . [N] greatest integer Given ._(92)U^(235)=235.1175"amu (atom)" , ._(56)Ba^(141)=140.9577 "amu (atom)" , ._(36)r^(92)=91.9263 "amu(atom)" , ._(0)n^(1)=1.00898 "amu", 1 "amu"=931 MeV//C^(2)

Knowledge Check

  • Complete the equation for the following fission process : ""_(92)^(235) U + _(0)^(1) n to _(38)^(90) Sr + . . .

    A
    `""_(54)^(143)Xe + 3 _(0)^(1) n `
    B
    `""_(54)^(145) Xe `
    C
    ` ""_(54)^(142) Xe + 3 _(0)^(1) n`
    D
    `""_(57) ^(142) Xe `

  • Complete the equation for the following fission process ._92 U^235 ._0 n^1 rarr ._38 Sr^90 +.... .

    A
    `._54 Xe^143 + 3 ._0 n^1`
    B
    `._54 Xe^145`
    C
    `._57 Xe^142`
    D
    `._54 Xe^142 ._0 n^1`

  • Fill in the blank ""_(92)U^(235) +""_(0)n^(1) to ? +""_(36)^(92)Kr + 3""_(0)^(1)n

    A
    `""_(56)^(141)Ba`
    B
    `""_(56)^(139)Ba`
    C
    `""_(56)^(139)Ba`
    D
    `""_(54)^(141)Ba`

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    When Uranium is bombarded with neutrons , it undergoes fission . The fission reaction can be written as : ""_(92) U^(235) + ""_(0) n^(1) to ""_(56) Ba^(141) + ""_(36) Kr^(92) + 3x + Q (energy) where three particles named x are produced and energy Q is released . What is the name of the particle x ?

    Which of the following elements is an isodiaphere of ._(92)^(235)U ?

    The compound unstable nucleus ""_(92) ^(236) U oftendecays in accordance with the following reaction ""_(92)^(236) U to ""_(54)^(140) Xe + ""_(38)^(94) Sr + other particles In the nuclear reaction presented above , the "other particle" might be

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