Complete the equation for the following fission process :
`""_(92)U^(235)+""_(0)n^(1)to""_(38)Sr^(0)+`…..

Options

A. `""_(54)Xe^(143)+3""_(0)n^(1)`
B. `""_(54)Xe^(145)`
C. `""_(52)Xe^(142)`
D. `""_(54)Xe^(142)+""_(0)n^(1)`

Explanation

In a nuclear reaction, atomic mass and charge remain conserved.
For a nuclear reaction to be completed the mass and charge number on both sides should be same.
If we complete the equation by choice a, then the reaction is
Total atomic number on LHS=`92+0=92`
`""_(92)U^(235)+""_(0)n^(1)to""_(38)Sr^(90)+""_(54)X^(143)+3""_(0)n^(1)`
Total atomic number on RHS
`38+54+0=92`
Total atomic number on LHS=`235+1=236`
Total atomic number on RHS
`=90+143+3xx1=236`