Home
Class 10
MATHS
Two chords AB and CD of a circle with ce...

Two chords AB and CD of a circle with centre O intersect each other at the point P. If ∠AOD =20° and ∠BOC = 30°, then ∠BPC is equal to?

A

`25^@`

B

`40^@`

C

`90^@`

D

`105^@`

Text Solution

Verified by Experts

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • TAMLUK HAMILTON HIGH SCHOOL

    UNITED BOOK HOUSE|Exercise EXERCISE|51 Videos

  • Theorems related to circle

    UNITED BOOK HOUSE|Exercise Exercise |21 Videos

Similar Questions

Explore conceptually related problems

Two chords AB and CD of a circle with centre O intersect each other at the point P. prove that AOD+ angle BOC = 2 angle PBC . If angle BOC are supplementary to each other, then prove that the two chords are perpendicular to each other.

Two chords AB, CD of a circle with centre O intersect each other at P. angleADP =23^@ and angleAPC = 70^@ , then the angleBCD is

Two chords AB and CD of circle having centre O intersect each other at P. If angleAPC = 40^@ , then angleAOC+angleBOD =

Two chords AB and CD of a cricle with centre O intersect at P. Prove that angleAOD+angleBOC= 2 angleBPC .

Two chords AB and CD of the circle with centre at O intersect each other at an internal point P of the centre. Prove that angle AOD+ angle BOC=2 angle BPC

If two chords AB and CD of a circle with centre, O, when producd intersect each other at the point P, prove that angle AOC- angle BOD=2 angle BPC .

If two chords AB and CD of a circle with centre O, when produce intersect each other at the point P, then prove angleAOC-angleBOD = 2angleBPC .

Two chords AC and BD of a circle intersect each other at the point O. If two tangents drawn at the points A and B intersect each other at the point P and two tangents drawn at the points C and D intersect at the point Q, prove that angle P+ angle Q =2 angle BOC. [GP-X]

Chords AB and CD of a circle intersect inside the circle at point E. If AE = 5.6, EB = 10, CE = 8, find ED.

Two chords AB and CD of a circle intersect at a internal point P of the circle. Prove that APxxBP=CPxxDP .

Home
Profile