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Let us consider a function f : R rarrR, ...

Let us consider a function f : `R rarrR`, defined by f(x) `=x^3 - 6`. Show that the mapping f is bijective.

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Knowledge Check

  • Let the function f : R to R be defined by f(x)= 2x + cos x , then f(x)-

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    onto but not one -one
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  • If the function f: R to R is defined by f(x)=x^(2)-6x-14 , then f^(-1)(2) is equal to -

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