Answer
Step by step text solution for The parabola y=x^2+p x+q cuts the straight line y=2x-3 at a point with abscissa 1. Then the value of pa n dq for which the distance between the vertex of the parabola and the x-axis is the minimum is p=-1,q=-1 (b) p=-2,q=0 p=0,q=-2 (d) p=3/2,q=-1/2 by MATHS experts to help you in doubts & scoring excellent marks in Class 11 exams.
|
Similar Questions
Explore conceptually related problems
Recommended Questions
- The parabola y=x^2+p x+q cuts the straight line y=2x-3 at a point with...
01:53
|
Playing Now - The value of p and q for whichp ,q are the roots of the equation x^2+p...
01:26
|
Play - If the line x-y-1=0 intersect the parabola y^(2)=8x at P and Q, then f...
04:03
|
Play - if |x|<1 then d(dx)[1+(p)/(q)x+(p(p+q))/(2!)((x)/(q))^(2)+
02:51
|
Play - If line x-2y-1=0 intersects parabola y^(2)=4x at P and Q, then find th...
02:35
|
Play - Let P(x) and Q(x) be two quadratic polynomials such that minimum value...
08:55
|
Play - यदि z=x-iy एवं z^(1/3)=p+iota q तब (x/p+y/q)//(p^2+q^2)=
03:31
|
Play - If one root is square of the other root of the equation x^2+p x+q=0, t...
05:15
|
Play - If line x-2y-1=0 intersects parabola y^(2)=4x at P and Q, then find th...
03:58
|
Play