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The locus of the midde points ofchords o...

The locus of the midde points ofchords of hyperbola `3x^2-2y^2+4x -6y=0` parallel to `y=2x` is

Text Solution

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Using `T = S_(1),` the equation of chord whose midpoint is (h, k) is
`3xh-2yk+2(x+h)-2y(y+k)=3h^(2)-2k^(2)+4h-6k`
`"or "x(3h+2)-y(2k+3)+…=0.`
Its slope is `(3h+2)/(2k+3)=2` as it is parallel to y = 2x.
`rArr" "3h-4k=4`
`rArr" "3x-4y=4,` which is required locus.
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Knowledge Check

  • The tangent to the hyperbola 3x^(2)-y^(2)=3 parallel to 2x-y+4=0 is:

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