If the probability of a six digit number...

If the probability of a six digit number `N` whose six digit are 1,2,3,4,5,6 written as random order is divisible by 6 is `p ,` then the value of `1//p` is__________.

Text Solution

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The correct Answer is:

Total number of cases = n(S) = 6!
Now sum the given digits is 1 + 2 + 3 + 4 + 5 + 6 = 21, which is divisible by 3.
Now we have to form the number which is divisible by 6, then we have to ensure that the digit in unit place is even.
implies Favorable cases = n(A) = `3 . 5!`
Hence, `P(A) = (3.5!)/(6!) = (1)/(2)`.

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