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Examine whether A= { x:x is a positive i...

Examine whether A= { x:x is a positive integer divisible by 3} is a subset of B= { x:x is a multiple of 5, x∈N }.

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The correct Answer is:
(a),(e ) , (g) , (h) ,(i), (k) are incorrect

We have set, A -' {1, 2, {3, 4}, 5}
(a) The statement {3, 4} `sub` A is incorrect because 3 `in` {3, 4}. however, `3 in A`.
(b) We know that the element of the set can be a set.
So, the statement {3, 4} `in A` is correct because {3, 4} is an element of A.
(c ) The statement {{ 3, 4}} ` in A` is correct because `{3, 4} in {{3, 4}} "and " {3, 4} in A.`
( d) The statement `1 in A` is correct because 1 is an element of A.
(e) The statement `1 sub A` is incorrect because an element of a set can never be a subset of the set.
(f) The statement `{1, 2, 5} sub A` is correct because each element of {1, 2, 5} is element of the set A
(g) The statement `{1, 2, 5} in A` is incorrect because set {1, 2, 5} is not an element of the set A.
(h) The statement `{1, 2, 3} sub A` is incorrect because `3 in {1, 2, 3 } ," however " 3 notin A`.
(i) The statement `phi in A` is incorrect because `(phi)` is a not an element of the set A.
(j) The statement `phi sub A` is correct because `phi ` is a subset of every set.
(k ) The statement `{phi} sub A` is incorrect because `phi in { phi}` however `phi notin A.`
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Knowledge Check

  • If A={x:x is a multiple of 3} and B={x:x is multiple of 5} then A-B is

    A
    `barAcapB`
    B
    `AcapbarB`
    C
    `barAcapbarB`
    D
    `bar(AcapB)`
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