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Find the angle made by a double ordinate...

Find the angle made by a double ordinate of length 2a at the vertex of the parabola `y^(2)=ax`.

Text Solution

Verified by Experts

The correct Answer is:
`90^(@)`
From the figure, y coordinate of point P is 4a.
So, from the equation of parabola
`(4a)^(2)=4axorx=4a`

Therefore, coordinate of point P are (4a,4a).
`:." "POM=45^(@)`
`:." "POQ=90^(@)`
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Knowledge Check

  • The vertex of the parabola y^2 = 4x + 4y is

    A
    `(1,-2)`
    B
    `(-1,2)`
    C
    `(2,1)`
    D
    `(-2, 1)`

  • The vertex of the parabola y^2 + 4x = 0 is

    A
    `(4,0)`
    B
    `(-4,0)`
    C
    `(-1,0)`
    D
    `(0,0)`

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