Answer
Step by step text solution for 0.80g is impure (NH_4)SO_4) was boiled with 100mL of 0.2N NaOH solution till all the NH_3 (g) evolved. The remaining solution was diluted to 250mL. 25mL of this solution was neutralized using 5mL of 0.2 NH_2 SO_4 solution. The percentage purity of the (NH_4)_2SO_4 sample is : by CHEMISTRY experts to help you in doubts & scoring excellent marks in Class 11 exams.
|
Similar Questions
Explore conceptually related problems
Knowledge Check
A
B
C
D
Submit
Similar Questions
Explore conceptually related problems
Recommended Questions
- 0.80g is impure (NH4)SO4) was boiled with 100mL of 0.2N NaOH solution ...
07:03
|
Playing Now - 0.7g of (NH(4))(2)SO(4) sample was boiled with 100mL of 0.2 N NaOH sol...
03:55
|
Play - 0.80g of impure (NH(4))(2) SO(4) was boiled with 100mL of a 0.2N NaOH ...
04:26
|
Play - (NH4)2SO4 का जलीय विलयन प्रदर्शित करता है
04:47
|
Play - 0.70g mixture of (NH(4))(2)SO(4) was boiled with 100 ml of 0.2 N NaOH ...
02:48
|
Play - Some amount of NH4 CI was boiled with 50ml of 0.75 N NaOH solution til...
Text Solution
|
Play - An impure ( NH4 )2SO4 Samples 3.6g Obtained by heating with NaOH NH3 T...
08:12
|
Play - Balance the following equations Fe2(SO4)3 + NH3 + H2O to Fe(OH)3 + (NH...
02:59
|
Play - NH3 गैस उत्पन्न करने हेतु अमोनियम सल्फेट की आवश्यक मात्रा जो कि 292 ग्...
05:49
|
Play