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0.80g is impure (NH4)SO4) was boiled wit...

`0.80g` is impure `(NH_4)SO_4)` was boiled with `100mL` of `0.2N NaOH` solution till all the `NH_3 (g)` evolved. The remaining solution was diluted to `250mL. 25mL` of this solution was neutralized using `5mL` of `0.2 NH_2 SO_4` solution. The percentage purity of the `(NH_4)_2SO_4` sample is :

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