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The pressure exerted by 6.0 g of methane...

The pressure exerted by `6.0 g` of methane gas in a `0.03 m^(3)` vessel at `129^(@)C` is: (Atomic masses of `C= 12.01, H= 1.01 and R= 8.314 JK^(-1)mol^(-1)`)

A

215216 Pa

B

13409 Pa

C

41648 Pa

D

31684 Pa

Text Solution

Verified by Experts

The correct Answer is:
C
According to the ideal gas eq.
`PV = nRT`
`P = V/(nRT) = 6/16 xx (8.314 xx 402)/(0.03) = 41648 Pa`
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