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What is the change in oxidation number o...

What is the change in oxidation number of carbon in the following reaction?
`CH_4 (g) + 4Cl_2(g) rarr CCl_4(l) + 4HCl(g)

A

0 to +4

B

`-4` to +4

C

0 to -4

D

`+4` to +4

Text Solution

Verified by Experts

The correct Answer is:
B
`CH_(4)(g) + 4Cl_(2)(g) to C Cl-(4)(I) + 4HCl (g)`
In the given reaction
Let Carbon oxidation number assumes to be x
H oxidation state is +1
In `CH_(4)`
`x + 4 xx 1=0`
`x=-4`
In `C Cl_(4)`
Cl oxidation state is -1
`x + 4 xx (-1) =0`
`x = +4`
Thus, Change in oxidation state of carbon is from `-4` to +4
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