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What is the change in oxidation number o...

What is the change in oxidation number of carbon in the following reaction?
`CH_4 (g) + 4Cl_2(g) rarr CCl_4(l) + 4HCl(g)

A

0 to +4

B

`-4` to +4

C

0 to -4

D

`+4` to +4

Text Solution

Verified by Experts

The correct Answer is:
B

`CH_(4)(g) + 4Cl_(2)(g) to C Cl-(4)(I) + 4HCl (g)`
In the given reaction
Let Carbon oxidation number assumes to be x
H oxidation state is +1
In `CH_(4)`
`x + 4 xx 1=0`
`x=-4`
In `C Cl_(4)`
Cl oxidation state is -1
`x + 4 xx (-1) =0`
`x = +4`
Thus, Change in oxidation state of carbon is from `-4` to +4
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The oxidation number of carbon in CH_2Cl_2 is +4.

Identify the oxidised and reduced species in the following reactions: (a) CH_(4(g))+4Cl_(2(g))rarrC Cl_(4(g))+4HCl_((g)) (b) MnO_(2(s))+C_(2)H_(2)O_(4(aq.))overset(2H^(+))rarrMn_((aq.))^(2+)+2CO_(2(g))+2H_(2)O_((l)) (c ) I_(2(aq.))+2S_(2)O_(3(aq.))^(2-)rarr2I_((aq.))^(-)+S_(4)O_(6)^(2-) (d) Cl_(2(g))+2Br_((aq.))^(-)rarr2Cl_((aq.))^(-)+Br_(2(aq.))

Knowledge Check

  • What is the change in oxidation number of carbon in the following reaction? CH_(4(g))+4Cl_(2(g)) rarr C""Cl_((4(l))) +4HCl_((g))

    A
    `+4" to "+4`
    B
    `0" to "+4`
    C
    `-4" to "+4`
    D
    `0" to "-4`
  • What is the change in oxidation number of carbon in the following reaction? CH_(4)(g) + 4Cl_(2)(g) to C Cl_(4)(l) + 4HCl (g)

    A
    0 to +4
    B
    `-4` to +4
    C
    0 to -4
    D
    `+4` to +4
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