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The calculated spin only magnetic moment...

The calculated spin only magnetic moment of `Cr^(2+)` ion is

A

`4.90BM`

B

`5.92` BM

C

`2.84` BM

D

`3.87` BM

Text Solution

Verified by Experts

The correct Answer is:
A
Electronic configuration of `Cr[Ar]3d^(5)4s^(1)`
The electronic configuration of `Cr^(2+)[Ar]3d^(4)`
So, Number of unpaired electron is 4
Spin only magnetic moment `=`
`mu=sqrt(n(n+2))`
`=sqrt(4(4+2))`
`=4.9` B.M
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  • Spin only magnetic moment of Mn^(4+) ion is nearly

    A
    3 BM
    B
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    C
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    D
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  • The spin only magnetic moment of Mn^(4+) ion is nearly

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    3 BM
    B
    6 BM
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    D
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