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If the first ionisation energy of H-atom...

If the first ionisation energy of H-atom is 13.6 eV, then the second ionisation energy of He-atom is :

A

27.2 eV

B

40.8 eV

C

54.4 eV

D

108.8 eV

Text Solution

Verified by Experts

The correct Answer is:
C
Ionisation energy of an atom of atomic number, Z is given by
`I.E.=(I.E_(H)xxZ^(2))/(n^(2))=13.6xx(Z^(2))/(n^(2)) eV`
Thus, second ionisation energy for He-atom is given by
`I.E.=(13.6xx (2)^(2))/((1)^(2))eV rArr 54.4 eV`
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Knowledge Check

  • If ionising energy of H atom is 13.6 eV, then the second ionising energy of He should be

    A
    `13.6 eV`
    B
    `27.2 eV`
    C
    `54.4 eV`
    D
    Cannot be predicted

  • The ionisation energy of hydrogen atom is 13.6eV. What is the ionisation energy of He ?

    A
    `-27.2 eV`
    B
    `+27.2 eV`
    C
    `+54.4 eV`
    D
    `-54.4 eV`

  • The ionisation energy of H atom is 13.6 eV The inoisation energy of Li^(2+) law will be

    A
    54.4 eV
    B
    122.4 eV
    C
    13.6 eV
    D
    27.2 eV

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