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The uncertainty in the velocity of parti...

The uncertainty in the velocity of particle of mass `6.626xx10^(-28)`kg is `10^(-6)` m/sec. What is the uncertaintly in its position in m?

A

`(1)/(2pi)`

B

`(2.5)/(pi)`

C

`(4)/(pi)`

D

`(1)/(4pi)`

Text Solution

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The correct Answer is:
To solve the problem of finding the uncertainty in the position of a particle given its mass and the uncertainty in its velocity, we will use the Heisenberg Uncertainty Principle. Here’s a step-by-step solution: ### Step 1: Understand the Heisenberg Uncertainty Principle The Heisenberg Uncertainty Principle states that: \[ \Delta p \cdot \Delta x \geq \frac{h}{4\pi} \] where: - \(\Delta p\) is the uncertainty in momentum, - \(\Delta x\) is the uncertainty in position, - \(h\) is Planck's constant (\(6.626 \times 10^{-34} \, \text{J s}\)). ### Step 2: Relate momentum to mass and velocity Momentum (\(p\)) is given by the formula: \[ p = mv \] Thus, the uncertainty in momentum (\(\Delta p\)) can be expressed as: \[ \Delta p = m \cdot \Delta v \] where: - \(m\) is the mass of the particle, - \(\Delta v\) is the uncertainty in velocity. ### Step 3: Substitute into the uncertainty principle Substituting \(\Delta p\) into the Heisenberg Uncertainty Principle gives: \[ m \cdot \Delta v \cdot \Delta x \geq \frac{h}{4\pi} \] ### Step 4: Solve for \(\Delta x\) Rearranging the equation to solve for the uncertainty in position (\(\Delta x\)): \[ \Delta x \geq \frac{h}{4\pi m \Delta v} \] ### Step 5: Plug in the values Given: - Mass \(m = 6.626 \times 10^{-28} \, \text{kg}\), - Uncertainty in velocity \(\Delta v = 10^{-6} \, \text{m/s}\), - Planck's constant \(h = 6.626 \times 10^{-34} \, \text{J s}\). Now substituting these values into the equation: \[ \Delta x \geq \frac{6.626 \times 10^{-34}}{4\pi (6.626 \times 10^{-28})(10^{-6})} \] ### Step 6: Simplify the expression Calculating the denominator: \[ 4\pi (6.626 \times 10^{-28})(10^{-6}) = 4\pi \cdot 6.626 \times 10^{-34} \] Thus: \[ \Delta x \geq \frac{6.626 \times 10^{-34}}{4\pi \cdot 6.626 \times 10^{-34}} = \frac{1}{4\pi} \] ### Step 7: Final result The uncertainty in position is: \[ \Delta x \geq \frac{1}{4\pi} \, \text{m} \] ### Conclusion The uncertainty in the position of the particle is \(\frac{1}{4\pi} \, \text{m}\). ---

To solve the problem of finding the uncertainty in the position of a particle given its mass and the uncertainty in its velocity, we will use the Heisenberg Uncertainty Principle. Here’s a step-by-step solution: ### Step 1: Understand the Heisenberg Uncertainty Principle The Heisenberg Uncertainty Principle states that: \[ \Delta p \cdot \Delta x \geq \frac{h}{4\pi} \] where: ...
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Knowledge Check

  • The uncertainty in the velocity of particle of mass 6.626xx10^(-28) kg is 10^(6) m/sec. What is the uncertaintly in its position in nm?

    A
    `(1)/(2pi)`
    B
    `(2.5)/(pi)`
    C
    `(4)/(pi)`
    D
    `(1)/(4pi)`
  • The uncertainty in the velocity of a particle of mass 6.626 xx 10^(-31) kg is 1 xx 10^6 ms^(-1) . What is the uncertainty in its position (in nm) ? (h = 6.626 xx 10^(-34) Js)

    A
    `(1/(2pi))`
    B
    `((2.5)/(pi))`
    C
    `(4/(pi))`
    D
    `(1/(4pi))`
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    A
    `1.5 xx 10^-4 m`
    B
    `2.5 xx 10^-4 m`
    C
    `3.5 xx 10^-4 m`
    D
    `4.5 xx 10^-4 m`
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