Home
Class 12
PHYSICS
Assume that their is no repulsive force...

Assume that their is no repulsive force between the electrons in an atom but the force between positive and negative charges is given by Coulomb's law as usual. under such circumstances , calculate the ground state energy of a He- atom.

Answer

Step by step text solution for Assume that their is no repulsive force between the electrons in an atom but the force between positive and negative charges is given by Coulomb's law as usual. under such circumstances , calculate the ground state energy of a He- atom. by PHYSICS experts to help you in doubts & scoring excellent marks in Class 12 exams.

Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

In a hydrogen molecules, the attractive and repulsive force between the atoms are balanced at _________.

A water molecule has an electric dipole moment 6.4xx10^-30 Cm when it is in vapour state. The distance in metre between the centre of positive and negative charge of the molecule is

If the distance between two point charges is doubled and magnitude of charges are also doubled, the Coulomb's force between them will be

Explain the difference between the distribution of positive charge in Thomson's atomic model and Rutherford's atomic model.

What is the energy in joules, required to shift the electron of the hydrogen atom from the first Bohr orbit to the fifth Bohr orbit and what is the wavelength of the light emitted when the electron returns to the ground state? The ground state electron energy is -2.18 xx 10^-11 ergs.

When total attractive forces between two atoms approaching each other is greater than total repulsive force then, potential energy of the system ________.

The Coulomb's repulsive force between two point charges placed at distance d apart, is F. If the distance is increased to 2d then the repulsive force between the charges as compared to its previous value, will become A. 1//4 the previous distance B. 1//2 C. 3//4 D. same

The force of repulsion between two identical positive charges when kept with aseparation r in air is F. half the gap between the two charges is filled by a dielectric slab of dielectric constant = 4. thenthe new force of repulsion between those two charges becomes

Coulomb's force between two point charges separated by certain distance in air is F. If the charges are situated in medium at same place then Coulomb's force reduces to F//4 . The dielectric constant of medium will be

In a hydrogen atom, the distance between proton and electron is 5.3xx10^-11m . The electrical force of attraction between them will be

Home
Profile