Home
Class 12
CHEMISTRY
If NaCl is doped with 10^(-3) mole % of ...

If NaCl is doped with `10^(-3)` mole % of `SrCl_(2)`, what is the concentration of the cation vacancies?

Text Solution

Verified by Experts

Due to the addition of `SrCl_(2)` each `Sr^(2+)` ion replaces `2Na^(+)` ions, but occupies only one lattice point in place of two `Na^(+)` ion. This creates cation vacancy.
Number of moles of cation vacancies in 100 moles of NaCl is equal to `10^(-3)` mole.
Number of moles of cation vacancies in 1 mole of
`NaCl=(10^(-3))/(100)=10^(-5)`
Total number of cation vacancies
`=10^(-5)N_(A)=(10^(-5))xx (6.022xx 10^(23)"mol"^(-1))`
`=6.022 xx 10^(18)"mol"^(-1)`
Promotional Banner

Topper's Solved these Questions

  • THE SOLID STATE

    ARIHANT PUBLICATION|Exercise PART III (QUESTION FOR PRACTICE) (Long AnswerType Questions)|8 Videos

  • THE SOLID STATE

    ARIHANT PUBLICATION|Exercise PART III (QUESTION FOR ASSESSMENT) (Multiple Choice Type Questions)|3 Videos

  • THE SOLID STATE

    ARIHANT PUBLICATION|Exercise PART III (QUESTION FOR PRACTICE) (Short Answer Type I Questions)|17 Videos

  • SURFACE CHEMISTRY

    ARIHANT PUBLICATION|Exercise CHAPTER PRACTICE ( LONG ANSWER TYPE QUESTIONS)|1 Videos

Similar Questions

Explore conceptually related problems

Find the mole fraction of 10% NaOH solution.

A + 2B rarr 3C + 2D . In this reaction the rate of disapperance of B is 1 xx 10^(-3) mol L^(-1) S^(-1) . What will be Rate of change of concentration of A and C ?

A+2B to 3C + 2D The rate of disappearance of B is 0.5 xx 10^(-3) mol L ""^(-1)" s"^(-1) . What will be rate of change in concentration of A and C?

5.85 g of NaCl is dissolved in 90 g water what is the mole fraction of NaCl ?

For a reaction K=2xx10^-2 mole lit^-1 sec^-1 . If the concentration of the reactant is IM, the half life period of the reaction is