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In a first order reaction, the reactant ...

In a first order reaction, the reactant concentration decreases from 0.8 M to 0.4 M in 15 min. What is the time taken for the concentration to change from 0.1 M to 0.025 M?

Text Solution

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Let, `a= 0.8" M", a -x =0.4" M", t=15" min".`
For first order reaction,
`k = (2.303)/( t) log"" (1)/( a-x) = (2.303)/( 15) log"" (0.8)/( 0.4) = 0.462" min"^(-1)`
`therefore` Time taken for 0.1 M to 0.025 M can be calculated as
` t = (2.303)/( k) log"" (a)/( a-x)`
`= (2.303)/( 0.0462) log "" (0.1)/( 0.025) = 30" min"`
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