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In which case splitting will belarger, 3...

In which case splitting will belarger, 3d-orbital or 4d-orbital?

Text Solution

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The correct Answer is:
4d-orbital
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Knowledge Check

  • The compound in which carbon used only sp^3 - hybrid orbitals for bond formation is:

    A
    HCOOH
    B
    `NH_2CONH_2`
    C
    `(CH_3)_3C . OH`
    D
    `(CH_3)_3CCHO`

  • The compound in which carbon atom uses only its sp^ 3 - hybrid orbitals for bond formation is :

    A
    HCOOH
    B
    `(H_2N)_2CO`
    C
    `(CH_3)_3COH`
    D
    `CH_3CHO`

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