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An element has a body centered cubic (bc...

An element has a body centered cubic (bcc) structure with a cell edge of 288pm. The atomic radius is:

A

`(sqrt2)/(4)xx288` pm

B

`(4)/(sqrt3)xx288` pm

C

`(4)/(sqrt2)xx288` pm

D

`(sqrt3)/(4)xx288` pm

Text Solution

Verified by Experts

The correct Answer is:
D
For BCC,
`r=(sqrt3)/(4)a`
Given : a=288 pm (a = edge length, r=radius)
`r=(sqrt3)/(4)xx288` pm
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Knowledge Check

  • An element has a body centered cubic (bcc) structure with a cell edge of 288 pm. The atomic radius is

    A
    `sqrt(3)/4 times 288` pm
    B
    `sqrt(2)/4 times 288` pm
    C
    `4/sqrt(3) times 288` pm
    D
    `4/sqrt(2) times 288` pm

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    A
    `6.02 xx 10^(24)` atoms
    B
    `12.09 xx 10^(23)` atoms
    C
    `24.16 xx 10^(23)` atoms
    D
    `29.88 xx 10^(24)` atoms

  • An element 'A' has face-centered cubic structure with edge length equal to 361pm .The apparent radius of atom 'A' is:

    A
    127.6 pm
    B
    180.5 pm
    C
    160.5 pm
    D
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