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Two identical charged spheres suspended ...

Two identical charged spheres suspended from a common point by two mass-less strings of length `l` are initially at a distance d ( `d ltlt l`) apart because of their mutual repulsion . The charge begins to leak from both the spheres at a constant rate. As a result the charge approach each other with a velocity `v`. Then as a function of distance `x` between them .

A

`Vpropx^((1)/(2))`

B

`Vpropx`

C

`Vpropx^((1)/(2))`

D

`Vpropx^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • Two identical charged spheres suspended from a common point by two massless strings of length l are initially a distance d ( d ltlt l) apart because of their mutual repulsion . The charge begins to leak from both the spheres at a constant rate As a result the charge approach each other with a velocity v . Then as a function of distance x between them .

    A
    `vprop x^(1//2)`
    B
    `v propx`
    C
    `v prop x^(1//2`
    D
    `c propx^(-1)`

  • Two identical charged spheres suspended from a common point by two massless strings of length l are initially a distance d(d lt ltl) apart because of their mutual repulsion. The charge begins to leak from both the spheres at a constant rate. As a result charges approach each other with a velocity v. Then as a function of distance x between them,

    A
    (a) `vpropx^-1`
    B
    (b) `vpropx^(1/2)`
    C
    (c) `vpropx`
    D
    (d) `vpropx^(-1/2)`

  • Two identical charged spheres suspended from a common point by two massless strings of lengths l, are initially at a distance d (d lt lt l) apart because of their mutual repulsion. The charges begin to leak from both the spheres at a constant rate. As a result, the spheres approach each other with a velocity v. Then v varies as a function of the distance x between the spheres, as :

    A
    `v prop x^(1/2)`
    B
    `v prop x`
    C
    `v prop x^(1/2)`
    D
    `v prop x^(-1)`

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