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An electron is accelerated from rest thr...

An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is `1.227 xx 10^(-2)` nm, the potential difference is:

A

`10^(2) V`

B

`10^(3)` V

C

`10^(4)` V

D

10 V

Text Solution

Verified by Experts

The correct Answer is:
C

De-broglie wavelength of the electron
`lambda = (12.27)/(sqrt(v))Å` where, v is potential difference
`sqrt(v) = (12.27 xx 10^(-10))/(1.227 xx 10^(-11)) = 10^(2)`
`therefore v = 10^(4)` volts
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Knowledge Check

  • Wavelength of an electron accelerated through a potential difference of 1 volt is

    A
    ` 12 . 27 Å `
    B
    `1.234 Å `
    C
    1 micron
    D
    1 fermi
  • A electron beam particle is accelerated from rest through a potential difference of V volt. The speed of the particle is

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    `sqrt((2eV)/(m))`
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    `(m)/(e V)`
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    `sqrt(me V)`
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    `sqrt((4e V)/(m))`.
  • An electron of charge e and mass m is accelerated from rest by a potential difference V . the de Broglie wavelength is

    A
    Directly proportional to the square root of potential difference.
    B
    Inversely proportional to the square root of potential difference.
    C
    Directly proportional to the square root of electron mass
    D
    Inversely proportional of the cube root of electron mass
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