An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is `1.227 xx 10^(-2)` nm, the potential difference is:

Options

A. `10^(2) V`
B. `10^(3)` V
C. `10^(4)` V
D. 10 V

Answer

C

Explanation

De-broglie wavelength of the electron
`lambda = (12.27)/(sqrt(v))Å` where, v is potential difference
`sqrt(v) = (12.27 xx 10^(-10))/(1.227 xx 10^(-11)) = 10^(2)`
`therefore v = 10^(4)` volts