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3.7 g of a gas at 25^(@)C occupied the s...

`3.7 g` of a gas at `25^(@)C` occupied the same volume as `0.184 g` of hydrogen at `17^(@)C` and at the same pressure. The molecular mass of the gas is

A

`0.024`

B

`39.14`

C

`41.33`

D

`59.14`

Text Solution

Verified by Experts

The correct Answer is:
C
For hydrogen, `w= 0.184g, T= 17+273= 290K, M= 2`
From `pV= (w)/(M)RT= (0.184)/(2)xx R xx 290" ""……….."(i)`
For unknown gas, `w= 3.7g, T= 25+273= 298K, M= ?`
`pV= (3.7)/(M)xx R xx 298" ""…………"(ii)`
From Eqs. (i) and (ii) `(3.7)/(M) xx R xx 298= (0.184)/(2)xx R xx 290" or "M= (23.7xx 298xx 2)/(0.184xx 290)= 41.33`.
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