Consider the redox reaction in acidic medium:
`Mn^(2+) + BiO_3^(-) to MnO_4^(-) + Bi^(3+)` .Choose the correct statement from the following:

Options

A. The total electrons involved in the balanced chemical equation is 5
B. Two moles of electrons are donated by per mole of `BiO_3^(-)`
C. 2.8 mol of `H^(+)` are required for the change one mole of `BiO_3^(-)` to `Bi^(3+)`
D. Acid is used as reducing agent in this reaction

Answer

C

Explanation

In this reaction, `BiO_3^(-)` is reduced by accepting electrons which are donated by `Mn^(2+)` that is getting oxidized. The balanced equation is : `2Mn^(2+) + 5BiO_3^(-) + 14H^(+) to 2MnO_4^(-) + 7H_2O`
From the balanced equation, it is clear that total of 10 electrons are involved in the reaction, and 2.8 mol of `H^(+)` are required by per mole of `BiO_3^(-)`