Total number of voids in 0.5 mole of a compound forming hexagonal closed packed structure are

Options

A. `6.022xx10^(23)`
B. `3.011xx10^(23)`
C. `9.034xx10^(23)`
D. `4.516xx10^(23)`

Answer

C

Explanation

In hcp, for every particles there are two tetrahedral and one octahedral voids associated. Hence in 0.5 mole compound, the total number of voids = `3xx0.5xx6.023xx10^(23)=9.034xx10^(23)`