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Total number of voids in 0.5 mole of a c...

Total number of voids in 0.5 mole of a compound forming hexagonal closed packed structure are

A

`6.022xx10^(23)`

B

`3.011xx10^(23)`

C

`9.034xx10^(23)`

D

`4.516xx10^(23)`

Text Solution

Verified by Experts

The correct Answer is:
C
In hcp, for every particles there are two tetrahedral and one octahedral voids associated. Hence in 0.5 mole compound, the total number of voids = `3xx0.5xx6.023xx10^(23)=9.034xx10^(23)`
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Knowledge Check

  • The C0ordination number of a metal crystallizing in a hexagonal close packed structure is

    A
    12
    B
    4
    C
    8
    D
    6

  • The total number of octahedral void(s) epr atom present in a cubic close packed structure is

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    2
    B
    4
    C
    1
    D
    3

  • The total number of octahedral void(s) per atom present in a cubic close packed structure is

    A
    2
    B
    4
    C
    1
    D
    3

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