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Assertion : H-S-H bond angle in H2S is c...

Assertion : H-S-H bond angle in `H_2S` is closer to `90^@` but: H-O-H bond angle in `H_2O` is `104.5^@`.
Reason : lp-lp repulsion is stronger in `H_2S` than in `H_2O`.

A

If both Assertion and Reason are correct and Reason is the correct explanation of Assertion

B

If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion

C

If Assertion is correct , but Reason is incorrect

D

If both Assertion and Reason are incorrect

Text Solution

Verified by Experts

The correct Answer is:
C
Due to lower electronegativity of S as compared to O, the bond pairs of H-S bonds lie away from S in `H_2S` as compared to bond pairs of O-H bonds in `H_2O`.As a result, bp-bp repulsions in `H_2S` are weaker than in `H_2O` and hence H-S-H bond angle in `H_2S` is smaller `(90^@)` than H-O-H bond angle in `H_2O(104.5^@)`.
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The 'H-S-H' bond angle in 'H_2 S' is '92 . 2.whereas the 'H-O-H' bond angle in 'H_2 O' is '.104 .5, why?

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Knowledge Check

  • The 'O-O-H' bond angle in 'H_2 O_2' is

    A
    `106^circ`
    B
    `109^circ 28^'`
    C
    `120^circ`
    D
    `94.8^circ`

  • The O-O-H bond angle in H_2O_2 in the gas phase is

    A
    `106^@`
    B
    `109^@28'`
    C
    `120^@`
    D
    `94.8^@`

  • The O-O-H bond angle in H_(2),O_(2) in the gas phase is

    A
    `106^(@)`
    B
    `109^(@)28`
    C
    `120^(@)`
    D
    `94.8^(@)`

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