Home
Class 12
CHEMISTRY
Equivalent conductivity of 1M CH(3)COOH ...

Equivalent conductivity of 1M` CH_(3)COOH` is `10 Omega^(-1) cm^(2) eq^(-1)` and at infinite dilution `200 Omega^(-1) cm^(2) eq^(-1)` . Hence, percentage ionisation of `CH_(3)`COOH is

A

0.05

B

0.02

C

0.04

D

0.01

Text Solution

Verified by Experts

The correct Answer is:
D

`x=(wedge_(c ))/(wedge_(0))=10/200=0.05`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    BRILLIANT PUBLICATION|Exercise Questions|17 Videos
  • ELECTROCHEMISTRY

    BRILLIANT PUBLICATION|Exercise Level -I|50 Videos
  • ELECTROCHEMISTRY

    BRILLIANT PUBLICATION|Exercise LEVEL-I|35 Videos
  • D & F BLOCK ELEMENTS

    BRILLIANT PUBLICATION|Exercise Level -II|38 Videos
  • GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS

    BRILLIANT PUBLICATION|Exercise LEVEL - II (ASSERTION - REASON) |5 Videos

Similar Questions

Explore conceptually related problems

The eqv Ivalent conductivity of H_(2)SO_(4) at infinite dilution is 384 Omega^(-1) cm^(2) eq^(-1) . If 49 g H_(2)SO_(4) per litre is present in solution and specific resistance is 18.4 Omega calculate the degree of dissociation.

IUPAC name of CH_3CH(OH)CH_2COOH is:

Knowledge Check

  • If the equivalent conductance of 1 M benzoic acid is 12.8 ohm^(-1) cm^(2) eq^(-1) and if conductance of benzoate ion and H^(+) ions are 42 and 288.42 ohm^(-) cm^(2) eq^(-1) respectively, its degree of dissociation is:

    A
    0.39
    B
    0.039
    C
    0.0035
    D
    0.0035
  • If equivalent conductance of 1 M benzoic acid is 12.8 Omega^-1 ~cm^2 and if the conductance of benzoate ion and H^* ion are 42 and 288.42 Omega^-1 ~cm^2 respectively, its degree of dissociation is

    A
    39%
    B
    3.9%
    C
    0.35%
    D
    0.039 %
  • Equivalent conductance of NaCl, HCl and fC_2 fH_5 COONa at infinite dilution are 126.45 426.16 and' 91 cdot ohm ^-1 ~cm^2 respectively. The equivalent conductance of fC_2 H_5 COOH is

    A
    201.28 ohm^-t ~cm^2
    B
    390.71 ohm^-1 ~cm^2
    C
    698.28 ohm^-1 ~cm^2
    D
    540.48 ohm^-1 ~cm^2
  • Similar Questions

    Explore conceptually related problems

    The molar conductivity of acetic acid solution at infinite dilution is 390.7 Omega^-1 cm^2 mol^-1 . Calculate the molar conductivity of 0.01 M acetic acid solution, given that the dissociation constant of acetic acid is 1.8 xx 10^-5

    The conductivity of a saturated solution of a springly soluble salt, MX_(2) is found to be 4.0xx 10^(-6) Omega^(-1) cm^(-1) . If lamda_(m)^(oo) ((1)/(2) M^(2+)) = 50.0Omega^(-1) cm^(2) mol^(-1) and lamda_(m)^(oo) (X^(-)) = 50 Omega^(-1) cm^(2) mol^(-1) , the solubility product of the salt is about

    The limiting molar conductivities of HCl, CH_(3) COONa and NaCl are respectively 425, 90 and 125 mho cm^(2) mol^(-1) at 25^(@)C . The molar conductivity of 0.1 M CH_(3)COOH solution is 7.8 mho cm^(2) mol^(-1) at the same temperature. The degree of dissociation of 0.1 M acetic acid solution at the same temperature is

    The conductivity of a saturated solution of a sparingly soluble salt, MX, is found to be 4.0 x× 10^(-5) Okmega^(-1) cm^(-1) If lambda_(m)^(infty) (1/2M^(2+))=50.0 Omega^(-1) cm^(2) mol^(-1) and lambda_(m)^(2+)(X^(-)=50 Omega^(-1) cm^(2) mol^(-1)) the solubility product of the salt is about

    IUPAC name of CH_(3)CH(OH)CH_(2)CH_(2)COOH is: