Home
Class 11
PHYSICS
Tube A has both ends open while tube B h...

Tube `A` has both ends open while tube `B` has one closed, otherwise they are identical. The ratio of fundamental frequency of tube `A and B` is

A

`1 : 2`

B

`1 : 4`

C

`2 : 1`

D

`4 : 1`

Text Solution

Verified by Experts

The correct Answer is:
C
The fundamental frequency for an open pipe is
`f=(v)/(lamda)`
`l=(lamda)/(2),lamda=2l`
`f_("open")=(v)/(2l)`
`l=(lamda)/(4)`
`lamda=4l,f_("closed")=(v)/(lamda)=(v)/(4l)`
`(f_("open"))/(f_("closed"))=(f_(A))/(f_(B))=(v)/(2l)xx(4l)/(v)=2:1`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • WAVES AND OSCILLATIONS

    ALLEN |Exercise Part-1(Exercise-05)[B]|42 Videos

  • WAVES AND OSCILLATIONS

    ALLEN |Exercise Part-1(Exercise-04)[B]|13 Videos

  • SEMICONDUCTORS

    ALLEN |Exercise Part-3(Exercise-4)|50 Videos

Similar Questions

Explore conceptually related problems

Two narrow cylindrical pipes A and B have the same length. Pipe A is open at both ends and is filled with a monoatomic gas of molar mass M_(A) . Pipe B is open at one end and closed at the other end, and is filled with a diatomic gas of molar mass M_(B) . Both gases are at the same temperature. (a) If the frequency of the second harmonic of the fundamental mode in pipe A is equal to the frequency of the third harmonic of the fundamental mode in pipe B , determine the value of M_(B)//M_(B) . (b) Now the open end of pipe B is also closed (so that the pipe is closed at both ends). Find the ratio of the fundamental frequency in pipe A to that in pipe B .

A cylindrical tube, open at both ends, has a fundamental frequency f in air . The tube is dipped vertically in water so that half of its length is in water. The fundamental frequency of the air column is now (a) f // 2 (b) 3 f // 4 (C ) f (d) 2f

An open pipe is suddenly closed at one end with the result that the frequency of third harmonic of the closed pipe is found to be higher by 100 Hz then the fundamental frequency of the open pipe. The fundamental frequency of the open pipe is

In which test tube, reaction has occurred ? Write the balanced chemical equation for the reaction.

For a certain organ pipe, three successive resonance frequencies are observer at 425 , 595 and 765 H_(Z) respectively. Taking the speed of sound in air to be 340 m//s , (a) explain whether the pipe is closed at one or open at boyh ends. (b) determine the fundamental frequency and length of the pipe.

An open glass tube is immersed in mercury in such a way that a length of 8 cm extends above the mercury level. The open end of the tube is then closed and sealed and the tube is raised vertically up by additional 46 cm. what will be length of the air column above mercury in the above now ? (Atmospheric pressure = 76 cm of Hg)

A flute which we treat as a pipe open at both ends is 60 cm long. (a) What is the fundamental frequency when all the holes are covered? (b) How far from the mouthpieces should a hole be uncovered for the fundamental frequency to be 330 H_(Z) ? Take speed of sound in air as 340 m//s .

An organ pipe of length L is open at one end and closed at other end. The wavelengths of the three lowest resonating frequencies that can be produced by this pipe are

A tube, closed at one end and containing air, produces, when excited, the fundamental note of frequency 512 Hz . If the tube is open at both ands the fundamental frequency that can be excited is (in Hz)

A horizontal oriented tube AB of length 5m rotates with a constant angular velocity 0.5 rad/s about a stationary vertical axis OO' passing through the end A. the tube is filled with ideal fluid. The end of the tube is open, the closed end B has a very small orifice. The velocity with which the liquid comes out from the hole (in m/s) is

Home
Profile