An electric dipole is placed in a uniform electric field `vec(E )` of magnitude `40N//C`. Graph shows the magnitude of the square on the dipole versus the angle `theta` between the field `vec(E )` and the dipole moment `vec(p)`. The magnitude of dipole moment `vec(p)` is equal to:

Options

A. `1.25xx10^(-28) C-m`
B. `2.0xx10^(-25)C-m`
C. `2.5xx10%^(-28)C-m`
D. `5.0xx10^(-28)C-m`

Answer

A

Explanation

`vectau=vecpxxvecErArrtau_("max")=pE rArr50xx10^(-28)=p.40`
`rArrp=1.25xx10^(-28)C-m`