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An electric dipole is placed in a unifor...

An electric dipole is placed in a uniform electric field `vec(E )` of magnitude `40N//C`. Graph shows the magnitude of the square on the dipole versus the angle `theta` between the field `vec(E )` and the dipole moment `vec(p)`. The magnitude of dipole moment `vec(p)` is equal to:

A

`1.25xx10^(-28) C-m`

B

`2.0xx10^(-25)C-m`

C

`2.5xx10%^(-28)C-m`

D

`5.0xx10^(-28)C-m`

Text Solution

Verified by Experts

The correct Answer is:
A

`vectau=vecpxxvecErArrtau_("max")=pE rArr50xx10^(-28)=p.40`
`rArrp=1.25xx10^(-28)C-m`
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    the resultant force acting on the dipole is always zero.
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