Column I shows different charge distributions and short electric dipole at a distance x from the charge distributions. Column II gives the dependence of force acting on the dipole as of function of x.
Column I shows different charge distributions and short electric dipole at a distance x from the charge distributions. Column II gives the dependence of force acting on the dipole as of function of x.
Text Solution
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The correct Answer is:
(A) s (B) r (C) p (D) q
(P) Electric field due to uniformly `=sigma/(2 epsi_(0))`
Charge thin infinite disc
`F_("net")` on dipole `=0`
(Q) Electric filed due to uniformaly `=sigma_(x)/epsi_(0)`
charged infinite
`F_("net")` on dipole `=(rho ql)/epsi_(0)`
(R) Electric field due to uniform `=(2kl)/(x)`
infinite line of charge
`F_("net")` on.dipole `=(-2kl)/(x(x+l)) ~~(-2k lambda l)/x^(2)`
(S) Electric field due to uniformly `=(KQ)/x^(2)`
charged sphere
`F_("net")` on dipole `=(-KQq(2xl))/(x^(2)(x+l)^(2))~~(-KqQ(2xl))/x^(4)`
`~~(-2KqQl)/x^(3)`
Charge thin infinite disc
`F_("net")` on dipole `=0`
(Q) Electric filed due to uniformaly `=sigma_(x)/epsi_(0)`
charged infinite
`F_("net")` on dipole `=(rho ql)/epsi_(0)`
(R) Electric field due to uniform `=(2kl)/(x)`
infinite line of charge
`F_("net")` on.dipole `=(-2kl)/(x(x+l)) ~~(-2k lambda l)/x^(2)`
(S) Electric field due to uniformly `=(KQ)/x^(2)`
charged sphere
`F_("net")` on dipole `=(-KQq(2xl))/(x^(2)(x+l)^(2))~~(-KqQ(2xl))/x^(4)`
`~~(-2KqQl)/x^(3)`
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If the magnitude of intensity of electric field at a distance x on axial line and at a distance y on equatorial line on a given dipole are equal, then x : y is
If the magnitude of intensity of electric field at a distance x on axial line and at a distance y on equatorial line on a given dipole are equal, then x : y is
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