The sketch below show cross section so equipotential surfaces between two charged.Conductors that are shown in solid black.Some points on the equipotenital surfaces .near the conductors are marked as `A,B,C…. .` The arrangements lies in air (Take `epsilon_(0)=8.85xx10^(-12)C^(2)//Nm^(2)]`
Surfaces charge density of the plate is equal to
The sketch below show cross section so equipotential surfaces between two charged.Conductors that are shown in solid black.Some points on the equipotenital surfaces .near the conductors are marked as `A,B,C…. .` The arrangements lies in air (Take `epsilon_(0)=8.85xx10^(-12)C^(2)//Nm^(2)]`
Surfaces charge density of the plate is equal to
Surfaces charge density of the plate is equal to
A
`8.85xx10^(-10) C//m^(2)`
B
`-8.85xx10^(-10) C//m^(2)`
C
`17.7xx10^(-10) C//m^(2)`
D
`-17.7xx10^(-10) C//m^(2)`
Text Solution
Verified by Experts
The correct Answer is:
A
`E=(-dV)/(dr), sigma/in_(0)=(-30)/0.3`
`sigma=8.85xx10^(-12)xx10^(2)=8.85xx10^(-10) C//m^(2)`
`sigma=8.85xx10^(-12)xx10^(2)=8.85xx10^(-10) C//m^(2)`
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