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Figure shows the variation of the moment...

Figure shows the variation of the moment of inertia of a uniform rod, about an axis passing through itss centre and inclined at an angle `theta` to the length. The moment of inertia of the rod about an axis passing through one of its ends and making an angle `theta=(pi)/(3)` will be

A

`0.45 kg-m^(2)`

B

`1.8 kg-m^(2)`

C

`2.4 kg-m^(2)`

D

`1.5 kg-m^(2)`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • The moment of inertia of a thin uniform rod of mass M and length L about an axis passing through its midpoint and perpendicular to its length is I_(0) . Its moment of inertia about an axis passing through one of its ends and perpendicular to its length is .............

    A
    `I_(0)+(ML^(2))/(2)`
    B
    `I_(0)+(ML^(2))/(4)`
    C
    `I_(0)+2ML^(2)`
    D
    `I_(0)+ML^(2)`
  • The moment of inertia of a disc of uniform density about on axis coinciding with its diameter ……..

    A
    `(2)/(5)MR^(2)`
    B
    `MR^(2)`
    C
    `(1)/(4)MR^(2)`
    D
    `(1)/(2)MR^(2)`
  • If I_(1) is the moment of inertia of a uniform rod about an axis perpendicular to its length and passing through its one end. Now ring formed by bending the rod, if the moment of inertia about the diameter of ring I_(1) then (I_(1))/(I_(2)) = ……….

    A
    `(pi^(2))/(3)`
    B
    `(2pi^(2))/(3)`
    C
    `(4pi^(2))/(3)`
    D
    `(8pi^(2))/(3)`
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