Three solids of masses `m_(1),m_(2)` and `m_(3)` are connected with weightless string in succession and are placed on a frictionless table. If the mass `m_(3)` is dragged with a force T , the tension in the string between `m_(2)` and `m_(3)` is

Options

A. (a)`(m_(2))/(m_(1)+m_(2)+m_(3))T`
B. (b)`(m_(3))/(m_(1)+m_(2)+m_(3))T`
C. (c)`(m_(1)+m_(2))/(m_(1)+m_(2)+m_(3))T`
D. (d)`(m_(2)+m_(3))/(m_(1)+m_(2)+m_(3))T`

Answer

C

Explanation

`T=(m_(1)+m_(2)+m_(3))a`
`T-T_(1)=m_(3)a`
`T_(1)=T-m_(3)a`
`=T-(m_(3))/((m_(1)+m_(2)+m_(3))xxT)=(T(m_(1)+m_(2)))/((m_(1)+m_(2)+m_(3)))`