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A block of mass 15kg is placed on a long...

A block of mass 15kg is placed on a long trolley. The cofficient of fricition between the block and trolley is 0.18. The trolley accelerates from rest with `0.5m//s^(2)` for 20s. then what is the friction force:-

A

3.5N

B

133.3N

C

7.5N

D

N.O.T.

Text Solution

Verified by Experts

The correct Answer is:
C
Pseudo force `=15xx0.5=7.5N`
`f_("max")=15xx10xx0.18=27N`
`therefore f=7.5N`
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A block of mass 15 kg is placed on a long trolley. The coefficient of static friction between the block and the trolley is 0.18. The trolley accelerates from rest with 0.5 m s^(-2) for 20 s and then moves with uniform velocity. Discuss the motion of the block as viewed by (a) a stationary observer on the ground, (b) an observer moving with the trolley.

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Knowledge Check

  • A block rests on a rough inclined plane making an angle of 30° with the horizontal. The coefficient of static friction between the block and the plane is 0.8. If the frictional force on the block is 10 N, the mass of the block ((in kg) is .......... (Take g = 10 m//s^(2) )

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    C
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