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The electron in a hydrogen atom makes a ...

The electron in a hydrogen atom makes a transition from M shell to L-shell. The ratio of magnitude of initial to final acceleration of the electron is

A

`9:4`

B

`81 : 16`

C

`4:9`

D

`16:81`

Text Solution

Verified by Experts

The correct Answer is:
D
`V^(2)/r=V_(0)^(2)/(n^(2)r_(0) n^(2))=V_(0)^(2)/(r_(0) n^(4)) implies a_(1)/a_(2) =n_(2)^(4)/n_(1)^(4)=2^(4)/3^(4)=16/81`
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