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An electron collides with a fixed hydrog...

An electron collides with a fixed hydrogen atom in its ground state. Hydrogen atom gets excited and the colliding electron loses all its kinetic energy. Consequently the hydrogen atom may emits a photon corresponding to the largest wavelength of the Balmer series. The K.E. of colliding electron will be..

A

`10.2 eV`

B

`1.9 eV`

C

`12.1 eV`

D

`13.6 eV`

Text Solution

Verified by Experts

The correct Answer is:
C

Excitation upto `n=3` is required so that visible length is emitted upon de-excitation.
So required energy `=13.6 (1-1/9)=12.1 eV`
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Knowledge Check

  • To excite the hydrogen atom from its ground state to second excited state…. eV energy is required.

    A
    3.4
    B
    12.09
    C
    10.2
    D
    13.6
  • The potential energy of the orbital electron i the ground state of hydrogen atom is -E. What is its kinetic energy?

    A
    `(E)/(4)`
    B
    `(E)/(2)`
    C
    2E
    D
    4E
  • As an electron makes a transition from an excited state to the ground state of a hydrogen like atom/ion.

    A
    its kinetic energy increases but potential and total energy decreases
    B
    kinetic energy, potential energy and total energy decrease.
    C
    kinetic energy decreases, potential energy increases but total energy remain same.
    D
    kinetic energy and total energy decreases but potential energy increases.
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