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A vector vec(A) of length 10 units makes...

A vector `vec(A)` of length `10` units makes an angle of `60^(@)` with a vector `vec(B)` of length `6` units. Find the magnitude of the vector difference `vec(A)-vec(B)` & the angles with vector `vec(A)`.

Text Solution

Verified by Experts

The correct Answer is:
`2sqrt(19), cos^(-1)""(7)/(2sqrt(19)) or tan^(-1)""(3sqrt(3))/(7)`
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Knowledge Check

  • If the magnitude of the vector product | vec(A) xx vec(B)| of two vector is equal to the magnitude of their scalar product | vec(A) . vec(B)| , then the angle between vec(A) and vec(B) is ……….

    A
    `pi/3`
    B
    `pi/6`
    C
    `pi/4`
    D
    `pi/2`

  • Let vec(a) and vec(b) be two unit vectors and theta is the angle between them. Then vec(a)+vec(b) is a unit vector if ……….

    A
    `theta=(pi)/(4)`
    B
    `theta=(pi)/(3)`
    C
    `theta=(pi)/(2)`
    D
    `theta=(2pi)/(3)`

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